WORKS BETTER ON MOZILLA FIREFOX
Quant 3rd DEC
1. There are 1 badger and 1 panderer. If each badger has 6 flavors and each panderer has 3 flavors, then what is the total number of ways of selecting 4 flavors from badger and 1 flavor from panderer?
2. Given 'A' works 25mins to produce 1 ton of oil and 'B' works 30mins to produce 1 ton of oil, If they work simultaneously, then in how many hours they can produce 15 tons of oil?
3. 1/2(10^6) =??
A. 5*10^5
& four other options were given.
4. Col A: (0.02)^2
Col B: (-0.05)^2
5. If -10 < = X < = 6, then what is the maximum possible greatest value of -X^2+X^4?
6. If length of the triangle is 16 and perimeter is 40, then what is the area of the rectangle?
7. If 'A' is three times of 'B' and 'B' is five times of 'C', then how many times is 'A' when compared to 'C'?
A.15
B.14x
C.15x
D.10x
& so on....
8. If the arithmetic mean of 4 boys salary is X and average of 3 girls salary is y, then
Col A: Mean of 7 members salary
Col B: (x+y)/2
9. Given that there are 'x' girls and boys are 4 more than girls, if the probability of girls from the total(G+B) is 3/7, then totally how many girls are there?
10. In a line, if x-intercept is given as 2 and Y-intercept is given as 8, then which of the following below is true?
A. y-intercept is always 4 times of x-intercept.
B. y-intercept is always 6 more than x-intercept.
& 3 more options were given
11. A graph is given, in that 2 lines are drawn. Line L1 is drawn from left-right downward and line L2 is drawn left-right upward.
Col A: Slope of line L1
Col B: Slope of line L2
(Given question is something like this)
12. There are 4 members and each of their salary is 'h' and the mean of their salary is 'x' dollars & there are other 3 members each of their salary is 2h and the mean of their salary is 'y' dollars.
Col A: Standard Deviation of salary of 4 members
Col B: Standard Deviation of salary of all 7 members
(Given question is similar to this).
10:10 PM
|
Labels:
QUANTATIVE
|
This entry was posted on 10:10 PM
and is filed under
QUANTATIVE
.
You can follow any responses to this entry through
the RSS 2.0 feed.
You can leave a response,
or trackback from your own site.
0 comments:
Post a Comment